[10000印刷√] x^3+y^3+z^3-3xyz formula 534633-X^3+y^3+z^3-3xyz formula

 Answer The Formula for x³ y³ z³ can be derived from the formula of x³ y³ z³ 3xyz x³ y³ z³ 3xyz = (x y z) (x² y² z² – xy – yz– zx) In order to find the formula of x³ y³ z³, we need to send 3xyz to the right side of equal signProve that the equation $x^3y^3z^33xyz=1$ defines a surface of revolution and find the analytical equation of its axis of revolution I think that I need to apply What must be subtracted from 4x^42x^36x^22x6 so that the result is exactly divisible by 2x^2x1?

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X^3+y^3+z^3-3xyz formula

[最も選択された] expand (1/x y/3)^3 232524

 The expansion is y^55y^4x10y^3x^210y^4x^35y^5x^4x^5 We need to use Pascal's Triangle, shown in the picture below, for this expansion Because the binomial is raised to the 5th power, we need to use the 5th row of the triangleCreated by T Madas Created by T Madas Question 3 (**) y x= e sin32x a) Use standard results to find the series expansion of y, up and including the term in x4 b) Hence find an approximate value for 01 2 0 e sin3x x dx FP2M , e sin3 3 6 52 2 3 4 53 ( ) 2 x x x x x x O x= − ,Expandcalculator expand \left(x1\right)^{3} en Related Symbolab blog posts Middle School Math Solutions – Equation Calculator Welcome to our new "Getting Started" math solutions series Over the next few weeks, we'll be

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Expand (1/x y/3)^3

70以上 derivative of tan(2x 3) 306725-Derivative of tan(2x+3)

The derivative of tan 2x is 2 sec 2 (2x) (ie) d/dx tan 2x = 2 sec 2 (2x) Explanation We know that the derivative of tan x is sec 2 x (ie) d/dx (tan x) = sec 2 x According to the chain rule, d/dx tan 2x = sec 2 (2x) d/dx (2x) Therefore, d/dx tan 2x = 2 sec 2 (2x)מחשבונים לאלגברה, חשבון אינפיטיסימלי, גאומטריה, סטטיסטיקה, וכימיה כולל הדרךY=tanh^3 (2x) u=2x → du = 2dx y=tanh^3 (u) z=tanu → dz= 1 (tan u)^2 du y=z^3 →dy = 3z^2 dz dy = 3z^2 dz dy = 3 (tanu )^2 dz dy = 3 (tanu )^2 * (1 (tan u)^2) du dy = 3 (tan 2x )^2 * (1 (tan

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Derivative of tan(2x+3)